I need help on this problem.

Solve and Graph.
|2x+(-2)|> 13+x

xDx wrote:3X < 15
I Believe that is the Correct answer

~xDx

\

Get "x" by itself!

The answer is....
x < 5

<------------0
<| | |>
-5 0 5

I have no idea what the heck you guys are doing!

lol, i didn't go through to see if your first steps were correct though!

girlb11 wrote:I need help on this problem.

Solve and Graph.
|2x+(-2)|> 13+x

I hope I'm not too late to this.

Anyway I assume that the brackets around the first set of numbers are absolute value brackets so that means you get two equations as such:

2x-2>13+x

and

-(2x-2)>13+x

We'll solve the first one first.

2x-2>13+x

Subtract X from both sides and subtract 2 from both sides.

x>15

That's one of your answers. Now the second equation:

-(2x-2)>13+x

Divide both sides by -1 to switch the negative sign to the other side. Keep in mind you need to switch the greater than sign to a less than sign.

2x-2<-13-x

Then add X to both sides and add 2 to both sides.

3x<-11

Solve for x.

x<-11/3

I think your late, she needed the know the problem on November 13th, but I don't know if she still needs to know it.

Wow thats hard

That's insane!